Simplify Semver Version Compare Logic

There's the standard npm semver version comparison library, but I have some simple logic to compare semver versions here: const versionA = '14.8.3'; const versionB = '15.1.1'; cons

Solution 1:

You can use localeCompare instead, with the numeric option (with numeric, comparison is such that "1" < "2" < "10"), which is exactly the logic you're looking for:

const versionA = '14.8.3';
const versionB = '15.1.1';
const versionC = '15.1.2';
const versionD = '15.1.10';
const versionE = '15.2.1';
const versionF = '15.11.1';

constisGreater = (a, b) => {
  return a.localeCompare(b, undefined, { numeric: true }) === 1;
};

// first argument version comes later than second argument:console.log(isGreater(versionB, versionA));
console.log(isGreater(versionC, versionB));
console.log(isGreater(versionD, versionC));
console.log(isGreater(versionE, versionD));
console.log(isGreater(versionF, versionE));

console.log('---');

// second comes before first:console.log(isGreater(versionA, versionB));

// same, return value should be false:console.log(isGreater(versionA, versionA));

Or, equivalently, you can pass the locale string

en-US-u-kn-true

as the second parameter instead of { numeric: true }.

Solution 2:

I believe this is logically the same and shorter, but not exactly stunning in it's simplicity

constisGreater = (a, b) => {

  const [majorA, minorA, patchA] = String(a).split('.').map(v =>Number.parseInt(v));
  const [majorB, minorB, patchB] = String(b).split('.').map(v =>Number.parseInt(v));

  if (majorA !== majorB) {
    return majorA > majorB;
  }

  if (minorA !== minorB) {
    return minorA > minorB;
  }

  return patchA > patchB;

};