Obtain Difference Between Two Dates In Years, Months, Days In Javascript

well, I found a lot of questions like that here trying to obtain the difference between 2 dates in years, month and days... But no answers that complete my requirement. So i wrote

Solution 1:

You can use moment.js to simplify this:

functiondifference(d1, d2) {
  var m = moment(d1);
  var years = m.diff(d2, 'years');
  m.add(-years, 'years');
  var months = m.diff(d2, 'months');
  m.add(-months, 'months');
  var days = m.diff(d2, 'days');

  return {years: years, months: months, days: days};
}

For example,

> difference(Date.parse("2014/01/20"), Date.parse("2012/08/17"))
Object {years: 1, months: 5, days: 3}

moment.js can also return human-readable differences ("in a year") if that's what you're really after.

Solution 2:

so this is my function, this receive two dates, do all the work and return a json with 3 values, years, months and days.

varDifFechas = {};

// difference in years, months, and days between 2 datesDifFechas.AMD = function(dIni, dFin) {
    var dAux, nAnos, nMeses, nDias, cRetorno
    // final date always greater than the initialif (dIni > dFin) {
        dAux = dIni
        dIni = dFin
        dFin = dAux
    }
    // calculate years
    nAnos = dFin.getFullYear() - dIni.getFullYear()
    // translate the initial date to the same year that the final
    dAux = newDate(dIni.getFullYear() + nAnos, dIni.getMonth(), dIni.getDate())
    // Check if we have to take a year off because it is not fullif (dAux > dFin) {
        --nAnos
    }
    // calculate months
    nMeses = dFin.getMonth() - dIni.getMonth()
    // We add in months the part of the incomplete Yearif (nMeses < 0) {
        nMeses = nMeses + 12
        }
    // Calculate days
    nDias = dFin.getDate() - dIni.getDate()
    // We add in days the part of the incomplete monthif (nDias < 0) {
        nDias = nDias + this.DiasDelMes(dIni)
    }
    // if the day is greater, we quit the monthif (dFin.getDate() < dIni.getDate()) {
        if (nMeses == 0) {
            nMeses = 11
        }
        else {
            --nMeses
        }
    }
    cRetorno = {"años":nAnos,"meses":nMeses,"dias":nDias}
    return cRetorno
}

DifFechas.DiasDelMes = function (date) {
    date = newDate(date);
    return32 - newDate(date.getFullYear(), date.getMonth(), 32).getDate();
}

hope this help people looking for a solution.

this is a new version that other guy did, seems to have no erros, hope this works better