How To Pass Php Variable To Javascript Function As Parameter
I want to pass php image url as javascript function parameter. Please let me know how can I do this. In javascript I am doing some editing work on image . How can I pass this p
Solution 1:
You need to enclose the PHP code within quotes like as
<buttontype="submit"onclick="demo('<?phpecho$imageurl;?>');" >
//^^ ^^
Within your Javascript as you were passing value within function but not capturing that value within your function demo()
function demo(obj)
{ //^^^ Capturing value within function using variable name objalert(obj);
}
Solution 2:
You have to wrap it with quotes and you have to close the button
<buttontype="submit"onclick='demo("<?phpecho$imageurl?>")' ></button>Solution 3:
<buttontype="submit"onclick="demo('<?phpecho$img;?>');" >Solution 4:
I found $img is your variable and in code you are trying to send $imageurl
<html><?php$image=$row['image'];
$img=$loc.'user/'.$image;
?><script>functiondemo(val1)
{
alert(val1);
}
</script><body><buttontype="submit"onclick=demo('<?phpecho$img?>') >Click Me</button></body></html>
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