Regex For "All The Digits Should Not Be Same For A Mobile Number"

Editted: I am new to regular expressions. I need a regex for a 10-digit mobile number which should not start with 0 or 1 and the same number cannot be repeated for all 10 digits.

Solution 1:

You can use this regex to check if all the numbers are the same.

(\d) is a capturing group, \1 matches against the capturing group {9} matches \1 9 times, you can edit that figure to suit. So This will tell you if ten numbers are the same.

(\d)\1{9}

JS

text.match(/(\d)\1{9}/g);

http://regexr.com/3efqd

Solution 2:

In your case, the mobile number is of format (9999) 999-9999 Hence , the regex should be

/\((\d)\1{3}\) \1{3}-\1{4}/.test("(9999) 999-9999")
"true"

/\((\d)\1{3}\) \1{3}-\1{4}/.test("(9999) 929-9999")
"false"

here, the split-up explanation of the regex is

\( -> matches the ( in your string

(\d) -> matches the first integer and capture it (so that we could backreference it later)

\1 -> picks the first captured element

{3} -> checks if the capture is repeating 3 times

(space) -> space

\1{3} -> checks if the capture is repeating 3 times(backreferencing)

- -> checks for hiphen

\1{4} -> checks if the capture is repeating 4 times

Solution 3:

public class regex {
public static void main(String[] args)
{
    String regex1 = "(\\d)\\1{9}";
    String regex2 = "[\\d]{10}";
    Scanner ssc = new Scanner(System.in);
    System.out.println("enter string:");
    String input = ssc.next();
    System.out.println(input.matches(regex2)&&(!input.matches(regex1)));

}
}

Solution 4:

If you use any formatting like a separators (-) you can use as follows

^([2-9])(\d{2})-(\d{3})-(\d{4})(?<!(\1{3}-\1{3}-\1{4}))$

This will allow first digit as only in range of [2-9] and phone number in format 234-234-2345

This also checks whether same number is used through out number.

Code break up:

**1st Capturing Group ([2-9])**
         Match a single character present in the list below [2-9]
         2-9 a single character in the range between 2 (index 50) and 9 (index 57) (case sensitive)
**2nd Capturing Group (\d{2})**
        \d{2} matches a digit (equal to [0-9])
        {2} Quantifier — Matches exactly 2 times
 **-** 
        matches the character - literally (case sensitive)
**3rd Capturing Group (\d{3})**
        \d{3} matches a digit (equal to [0-9])
        {3} Quantifier — Matches exactly 3 times
**-** 
        matches the character - literally (case sensitive)
**4th Capturing Group (\d{4})**
       \d{4} matches a digit (equal to [0-9])
       {4} Quantifier — Matches exactly 4 times
**Negative Lookbehind (?<!(\1{3}-\1{3}-\1{4}))**
          Assert that the Regex below does not match
**5th Capturing Group (\1{3}-\1{3}-\1{4})**
          This group matches with character in first group at positions where 
          our format number will have digits.. i.e., it matches if same 
          number is repeated in all positions 
   
**$**
         asserts position at the end of the string

Solution 5:

public static Boolean isValidMobileNumber(String mobileNo) {
        String pattern1 = mobileNo.charAt(0) + "{10}";
        String pattern2 = "[\\d]{10}";
        return (mobileNo.matches(pattern1) ||!mobileNo.matches(pattern2)) ? false : true;
}